Extraer coordenadas GPS de imágenes con PowerShell | Operating systems, scripting, PowerShell and security

$imagePath = 'C:\Users\juan\Desktop\recono\IMG_20171226_232738.jpg'
$imageProperties = New-Object -TypeName System.Drawing.Bitmap -ArgumentList $imagePath

[double]$LatDegrees = (([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(2).Value, 0)) / ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(2).Value, 4)));
[double]$LatMinutes = ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(2).Value, 8)) / ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(2).Value, 12));
[double]$LatSeconds = ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(2).Value, 16)) / ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(2).Value, 20));
[double]$LonDegrees = (([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(4).Value, 0)) / ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(4).Value, 4)));
[double]$LonMinutes = ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(4).Value, 8)) / ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(4).Value, 12));
[double]$LonSeconds = ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(4).Value, 16)) / ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(4).Value, 20));

"Latitude: $LatDegrees;$LatMinutes;$LatSeconds"
"Longitude: $LonDegrees;$LonMinutes;$LonSeconds"

$imagePath = 'C:\Users\juan\Desktop\recono\IMG_20171226_232738.jpg'

$imageProperties = New-Object -TypeName System.Drawing.Bitmap -ArgumentList $imagePath

[double]$LatDegrees = (([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(2).Value, 0)) / ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(2).Value, 4)));

[double]$LatMinutes = ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(2).Value, 8)) / ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(2).Value, 12));

[double]$LatSeconds = ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(2).Value, 16)) / ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(2).Value, 20));

[double]$LonDegrees = (([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(4).Value, 0)) / ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(4).Value, 4)));

[double]$LonMinutes = ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(4).Value, 8)) / ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(4).Value, 12));

[double]$LonSeconds = ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(4).Value, 16)) / ([System.BitConverter]::ToInt32( $imageProperties.GetPropertyItem(4).Value, 20));

"Latitude: $LatDegrees;$LatMinutes;$LatSeconds"

"Longitude: $LonDegrees;$LonMinutes;$LonSeconds"

Fuente

https://stackoverflow.com/questions/45136895/extracting-gps-numerical-values-from-byte-array-using-powershell

Publicado el día 1 de enero de 2018

CATEGORÍAS

Análisis forense, Gráficos, PowerShell, Seguridad

ETIQUETAS

Drawing, GPS, HTTPS, Jesús Niño Camazón, New-Object, System.Drawing, System.Drawing.Bitmap, value

CATEGORÍAS

ETIQUETAS

MÁS